Elections in India are Mathematically Flawed: [Sanvar’s Perspective]

While our ancestors developed the decimal system, zero as a number, negative numbers, arithmetic, algebra and trigonometry it’s quite striking as to how the same race could not develop a full proof election system.

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So here goes my theory:

In the present election format in India;

  1. To win a constituency: The candidate must get at least 1 more than 50% of the votes cast, and
  2. To win the elections overall: The party’s representatives must win in at least 1 more than 50% of all constituencies.

Now lets take a hypothetical case of a country and apply the above two

  1. There is 1 country going into national elections.
  2. There are 2 national parties contesting elections. (Each of them have 1 representative in each constituency)
  3. There are 100 constituencies in the country.
  4. There are 100 people living in each constituency. (All of them cast their votes)
  5. Hence, there are 100×100 = 10,000 people in the country

Ideally, for any party to win, they should obtain at least 5001 votes?

WRONG!

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Here’s how:

Imagine that in 1 constituency Party A representative get 51 votes, whereas Party B representative gets the remaining 49 votes. So, Party A wins in that constituency.

This happens in 51 constituencies: Party A representatives get exact 51 votes in each whereas Party B representatives get 49 votes. So, Party A wins in all 51 constituencies.

However, in the remaining 49 constituencies: Party B representatives get all 100 votes in each whereas Party A representatives get 0. So, Party B has won those 49 constituencies.

Now here’s the math:

Total Votes

Party A– 51 constituencies x 51 votes each = 2601

Party B– 51 constituencies x 49 votes each + 49 constituencies x 100 votes each = 7399

Total Constituencies Won

Party A– 51

Party B– 49

So, while 73.99% of the population voted for Party B, Party A comes into power.

Democracy? People’s choice?

Apathy of Indian Democracy

– Sanvar Oberoi

There

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