Elections in India are Mathematically Flawed: [Sanvar’s Perspective]
While our ancestors developed the decimal system, zero as a number, negative numbers, arithmetic, algebra and trigonometry it’s quite striking as to how the same race could not develop a full proof election system.
So here goes my theory:
In the present election format in India;
- To win a constituency: The candidate must get at least 1 more than 50% of the votes cast, and
- To win the elections overall: The party’s representatives must win in at least 1 more than 50% of all constituencies.
Now lets take a hypothetical case of a country and apply the above two
- There is 1 country going into national elections.
- There are 2 national parties contesting elections. (Each of them have 1 representative in each constituency)
- There are 100 constituencies in the country.
- There are 100 people living in each constituency. (All of them cast their votes)
- Hence, there are 100×100 = 10,000 people in the country
Ideally, for any party to win, they should obtain at least 5001 votes?
Imagine that in 1 constituency Party A representative get 51 votes, whereas Party B representative gets the remaining 49 votes. So, Party A wins in that constituency.
This happens in 51 constituencies: Party A representatives get exact 51 votes in each whereas Party B representatives get 49 votes. So, Party A wins in all 51 constituencies.
However, in the remaining 49 constituencies: Party B representatives get all 100 votes in each whereas Party A representatives get 0. So, Party B has won those 49 constituencies.
Now here’s the math:
Party A– 51 constituencies x 51 votes each = 2601
Party B– 51 constituencies x 49 votes each + 49 constituencies x 100 votes each = 7399
Total Constituencies Won
Party A– 51
Party B– 49
So, while 73.99% of the population voted for Party B, Party A comes into power.
Democracy? People’s choice?
– Sanvar Oberoi